0=-9.8x^2+45x+1

Solution for 0=-9.8x^2+45x+1 equation:

0=-9.8x^2+45x+1

We move all terms to the left:

0-(-9.8x^2+45x+1)=0

We add all the numbers together, and all the variables

-(-9.8x^2+45x+1)=0

We get rid of parentheses

9.8x^2-45x-1=0

a = 9.8; b = -45; c = -1;
Δ = b2-4ac
Δ = -452-4·9.8·(-1)
Δ = 2064.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{2064.2}}{2*9.8}=\frac{45-\sqrt{2064.2}}{19.6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{2064.2}}{2*9.8}=\frac{45+\sqrt{2064.2}}{19.6}
$